Lugh@futurology.todayM to Futurology@futurology.todayEnglish · 9 months agoChina's hyperloop maglev train has achieved the fastest speed ever for a train at 623 km/h, as it prepares to test at up to 1,000 km/h in a 60km long hyperloop test tunnel.robbreport.comexternal-linkmessage-square40fedilinkarrow-up1171arrow-down19
arrow-up1162arrow-down1external-linkChina's hyperloop maglev train has achieved the fastest speed ever for a train at 623 km/h, as it prepares to test at up to 1,000 km/h in a 60km long hyperloop test tunnel.robbreport.comLugh@futurology.todayM to Futurology@futurology.todayEnglish · 9 months agomessage-square40fedilink
minus-squareLostXOR@kbin.sociallinkfedilinkarrow-up6·edit-29 months agoI got an acceleration of 1.5G for the test, did you forget a factor of 2 or something? Still certainly not an enjoyable experience for passengers, but I assume it would accelerate over a much longer distance if a full track was built.
minus-squarethreelonmusketeers@sh.itjust.workslinkfedilinkEnglisharrow-up3·9 months agoI think I’d probably be fine with 1.5Gs as long as the jerk and snap were low.
minus-squareLostXOR@kbin.sociallinkfedilinkarrow-up2·9 months agoAdding in Earth’s gravity it’s about 1.8G total, applied at a weird angle, which might be too much for some people.
minus-squareGbyBE@discuss.tchncs.delinkfedilinkEnglisharrow-up1·9 months agoDid you also factor in that the train needs to come to a full stop in that 2km as well?
minus-squareLostXOR@kbin.sociallinkfedilinkarrow-up1·edit-29 months agoYes, I calculated the acceleration required to accelerate to 387MPH (173m/s) in 1km. v^2 = 2ax (173m/s)^2 = 2a(1000m) a = 14.96m/s^2 = 1.53g
I got an acceleration of 1.5G for the test, did you forget a factor of 2 or something? Still certainly not an enjoyable experience for passengers, but I assume it would accelerate over a much longer distance if a full track was built.
I think I’d probably be fine with 1.5Gs as long as the jerk and snap were low.
Adding in Earth’s gravity it’s about 1.8G total, applied at a weird angle, which might be too much for some people.
Did you also factor in that the train needs to come to a full stop in that 2km as well?
Yes, I calculated the acceleration required to accelerate to 387MPH (173m/s) in 1km.
v^2 = 2ax
(173m/s)^2 = 2a(1000m)
a = 14.96m/s^2 = 1.53g