• Risus_Nex@lemmy.world
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    6 months ago

    Isn’t it proof enough? Using the Sudoku example: there are certainly different levels of difficulties, depending on how many numbers are set in the beginning and other parameters. Checking if the solved answer is correct, is always the same “difficulty” - thus there is no correlation between the difficulty of the puzzle at the beginning and checking the Correctness. Some people might not be able to solve it, but they certainly can check if the solution is right

    • SorteKanin@feddit.dk
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      6 months ago

      Isn’t it proof enough?

      Unfortunately no. The question is a simplification of the P versus NP problem.

      The problem lies in having to prove that no method exists that is easy. How do you prove that no matter what method you use to solve the sudoku, it can never be done easily? You’ll need to somehow prove that no such method exists, but that is rather hard. In principle, it could be that there is some undiscovered easy way to solve sudokus that we don’t know about yet.

      I’m using sudokus as an example here, but it could be a generic problem. There’s also a certain formalism about what “easy” means but I won’t get into it further, it is a rather complicated area.

      Interestingly, it involves formal languages a lot, which is funny as you wouldn’t think computer science and linguistics have a lot in common, but they do in a lot of ways actually.

      • Phen@lemmy.eco.br
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        6 months ago

        You can solve any sudoku easily by trying every possible combination and seeing if they are correct. It’ll take a long time, but it’s fairly easy.

        • SorteKanin@feddit.dk
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          6 months ago

          Well it just so happens that the definition of “easy” in the actual problem is essentially “fast”. So under that definition, checking every single possible solution is not an “easy” method.